Quiz Creator - What are the two highest consecutive numbers that can be multiplied together to give a number less than 1,000?

Trivia Question 1: What are the two highest consecutive numbers that can be multiplied together to give a number less than 1,000?

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Answer: 31 & 32

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2024 update - Because we like you, here are some more free general knowledge trivia and quiz questions.

When it comes to finding the two highest consecutive numbers that can be multiplied together to give a number less than 1,000, it is important to consider the factors that will lead to the desired result. In this case, we are looking for the two largest consecutive numbers that, when multiplied, will result in a product less than 1,000.

In order to approach this problem, we need to start by considering the factors of 1,000. The factors of 1,000 are numbers that can be multiplied together to give the product of 1,000. Some of the factors of 1,000 include 1, 2, 4, 5, 8, 10, 20, 25, 40, 50, 100, 125, 200, 250, and 500.

Now, if we want to find the two highest consecutive numbers that can be multiplied together to give a number less than 1,000, we need to consider the factors that are closest to each other. In this case, the two highest consecutive numbers that can be multiplied together to give a number less than 1,000 are 31 and 32.

When we multiply 31 by 32, we get 992, which is less than 1,000. Therefore, 31 and 32 are the two highest consecutive numbers that can be multiplied together to give a number less than 1,000.

It is important to note that 31 and 32 are the highest consecutive numbers that meet this criteria because any higher numbers would result in a product greater than 1,000. By understanding the factors of 1,000 and considering the closest consecutive numbers, we are able to determine the two highest consecutive numbers that can be multiplied together to give a number less than 1,000.

In conclusion, the two highest consecutive numbers that can be multiplied together to give a number less than 1,000 are 31 and 32. By analyzing the factors and considering the closest consecutive numbers, we are able to find the solution to this problem.

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